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Fix 'return' statement usage in shell scripts
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commit
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1 changed files with 6 additions and 6 deletions
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@ -36,21 +36,21 @@ skipIndex=0
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chpasswdOptions=""
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useraddOptions=(--no-user-group)
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user="${args[0]}"; validateArg "username" "$user" "$reUser" || return 1
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pass="${args[1]}"; validateArg "password" "$pass" "$rePass" || return 1
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user="${args[0]}"; validateArg "username" "$user" "$reUser" || exit 1
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pass="${args[1]}"; validateArg "password" "$pass" "$rePass" || exit 1
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if [ "${args[2]}" == "e" ]; then
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chpasswdOptions="-e"
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skipIndex=1
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fi
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uid="${args[$((skipIndex+2))]}"; validateArg "UID" "$uid" "$reUid" || return 1
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gid="${args[$((skipIndex+3))]}"; validateArg "GID" "$gid" "$reGid" || return 1
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dir="${args[$((skipIndex+4))]}"; validateArg "dirs" "$dir" "$reDir" || return 1
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uid="${args[$((skipIndex+2))]}"; validateArg "UID" "$uid" "$reUid" || exit 1
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gid="${args[$((skipIndex+3))]}"; validateArg "GID" "$gid" "$reGid" || exit 1
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dir="${args[$((skipIndex+4))]}"; validateArg "dirs" "$dir" "$reDir" || exit 1
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if getent passwd "$user" > /dev/null; then
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log "WARNING: User \"$user\" already exists. Skipping."
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return 0
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exit 0
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fi
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if [ -n "$uid" ]; then
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