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Expose deno.exit() and add test.

This commit is contained in:
Ryan Dahl 2018-08-19 03:00:34 -04:00
parent 18d495c7d1
commit 790baae673
6 changed files with 40 additions and 11 deletions

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@ -1,6 +1,4 @@
// Copyright 2018 the Deno authors. All rights reserved. MIT license.
// Public deno module.
// TODO get rid of deno.d.ts
// export { pub, sub } from "./dispatch";
export { readFileSync } from "./os";
export { exit, readFileSync } from "./os";
export { libdeno } from "./globals";

5
tests/exit_error42.ts Normal file
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@ -0,0 +1,5 @@
import * as deno from "deno";
console.log("before");
deno.exit(42);
console.log("after");

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@ -0,0 +1 @@
before

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@ -7,7 +7,7 @@
import os
import sys
import subprocess
from util import pattern_match
from util import pattern_match, parse_exit_code
root_path = os.path.dirname(os.path.dirname(os.path.realpath(__file__)))
tests_path = os.path.join(root_path, "tests")
@ -27,21 +27,23 @@ def check_output_test(deno_exe_filename):
with open(out_abs, 'r') as f:
expected_out = f.read()
cmd = [deno_exe_filename, script_abs]
should_succeed = "error" not in script
expected_code = parse_exit_code(script)
print " ".join(cmd)
err = False
actual_code = 0
try:
actual_out = subprocess.check_output(cmd, universal_newlines=True)
except subprocess.CalledProcessError as e:
err = True
actual_code = e.returncode
actual_out = e.output
if should_succeed == True:
if expected_code == 0:
print "Expected success but got error. Output:"
print actual_out
sys.exit(1)
if should_succeed == False and err == False:
print "Expected an error but succeeded. Output:"
if expected_code != actual_code:
print "Expected exit code %d but got %d" % (expected_code,
actual_code)
print "Output:"
print actual_out
sys.exit(1)

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@ -1,5 +1,6 @@
# Copyright 2018 the Deno authors. All rights reserved. MIT license.
import os
import re
import shutil
import stat
import sys
@ -162,3 +163,13 @@ def pattern_match(pattern, string, wildcard="[WILDCARD]"):
string = string[(found + len(parts[i])):]
return len(string) == 0
def parse_exit_code(s):
codes = [int(d or 1) for d in re.findall(r'error(\d*)', s)]
if len(codes) > 1:
assert False, "doesn't support multiple error codes."
elif len(codes) == 1:
return codes[0]
else:
return 0

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@ -1,5 +1,5 @@
# Copyright 2018 the Deno authors. All rights reserved. MIT license.
from util import pattern_match
from util import pattern_match, parse_exit_code
def pattern_match_test():
@ -27,5 +27,17 @@ def pattern_match_test():
"[BAR]") == False, "expected wildcard to be set"
def parse_exit_code_test():
print "Testing util.parse_exit_code()..."
assert 54 == parse_exit_code('hello_error54_world')
assert 1 == parse_exit_code('hello_error_world')
assert 0 == parse_exit_code('hello_world')
def util_test():
pattern_match_test()
parse_exit_code_test()
if __name__ == '__main__':
util_test()